Tolongin plis nanti sore dikumpulkan:(((
Jawab:
16. Jawaban: 4 (E)
`17. Jawaban: [tex]\frac{- x + 4}{6x - 3}[/tex] (E)
Penjelasan dengan langkah-langkah:
16. Diketahui f(x) = x² - 7x + 3, tentukan f^-1 (-9):
f^-1 (x² - 7x + 3) = x
x² - 7x + 3 = -9
x² - 7x + 3 + 9 = 0
(x - 3)(x - 4) = 0
x = 3 atau x = 4
Maka,
f^-1 (-9) = x = 3 atau f^-1 (-9) = 4 (E)
17. f(g(x)) = [tex]\frac{(3x + 2) + 2}{2(3x + 2) - 3}[/tex] = [tex]\frac{3x + 4}{6x + 1}[/tex]
y = [tex]\frac{3x + 4}{6x + 1}[/tex]
y(6x+1) = 3x + 4
6xy + y = 3x + 4
6xy - 3x = 4 - y
x(6y - 3) = 4 - y
x = [tex]\frac{4 - y}{6y - 3}[/tex]
Maka,
(f o g)^-1 (x) = [tex]\frac{- x + 4}{6x - 3}[/tex] (E)
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